You are riding in an elevator on the way to the 18th floor of your dormitory. Th

Question

You are riding in an elevator on the way to the 18th floor of your dormitory. The elevator acceleration upward with a = 2.00 m/s^2. Beside you is the box containing your new computer; box and contents have a total mass of 36.0 kg. While the elevator is accelerating upward, you push horizontally on the box to slide it at constantt speed toward the elevator door. Part A If the coefficient of kinetic friction between the box and elevator floor is um_k = 0.34, what magnitude of force must you apply?

Explanation / Answer

Applied force is just equal to or slightly greater than the force of friction F the force of friction F= coefficient of kinetic friction x normal reaction R The difference of normal reaction R and weight mg provides the force 'f' which accelerates the box in the elevator in theupward direction.

R - mg = ma

R = mg+ma=m(g+a) = (36kg)(9.8+2)m/s^2 = 424.8 N

f = mu_k R = (0.34)(424.8 N) = 144.432 N

The force required to push the box is 144.432 N

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