a) Calculate the net electric field (magnitude and direction) at point A in the
ID: 1586840 • Letter: A
Question
a) Calculate the net electric field (magnitude and direction) at point A in the diagram of charges shown in the image. Each charge has a magnitude of 1 nC and each small division is 0.2m.
b) Calculate the net electric potential at point A.
Calculate the net electric field (magnitude and direction) at point A in the diagram of charges shown on the right. Each charge has a magnitude of 1 nC and each small division is 0.2m. The electric field due to a point charge qi is f where k is Coulom b's constant (k = 8.99%109 Nm, r is the distance between the charge and point A, and is a unit vector directed either away or towards q1. The net electric field is the vector sum of the electric fields Figure for questions #1 & 2 of each charge (account for direction) Calculate the net electric potential at point A in the diagram shown above. The net potential is the sum of the potential of the individual charges. (Note: The sign of the charge matters.) k The electric potential due to a point charge at a distance r from the charge q is V =Explanation / Answer
To calculate the magnitude of the electrostatic force that exists at A
EA=KQ1Q2/r2
= (8.99x109Nm2/C2)(10-9)2/(0.2)2
=224.75x10-9N
The direction of the electrostatic force that the charge1 feels due to the another charge2 is directed towards the charge2 and has a magnitude of 224.75x10-9N, while the electrostatic force that the charge2 feels due to the charge1 is directed toward the charge1 in accordance with Newton’s Third Law, and has a magnitude also of 224.75x10-9N
(b) net potential is the sum of the potential of the individual charges
Vnet=V1+V2+V3;
=kq/r+kq/r
=2kq/r
=2x(8.99x109Nm2/C2)(10-9)/(0.2)
=89.90V
Calculation may be wrong but comcept is right.
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