1)A small object has a mass of 3.3 10-3 kg and a charge of -35 µC. It is placed
ID: 1586469 • Letter: 1
Question
1)A small object has a mass of 3.3 10-3 kg and a charge of -35 µC. It is placed at a certain spot where there is an electric field. When released, the object experiences an acceleration of 2.37 103 m/s2 in the direction of the +x axis. Determine the magnitude and direction of the electric field
2)The total electric field E consists of the vector sum of two parts. One part has a magnitude of E1 = 1387 N/C and points at an angle 1 = 39° above the +x axis. The other part has a magnitude of E2 = 1560 N/C and points at an angle 2 = 57° above the +x axis. Find the magnitude and direction of the total field. Specify the directional angle relative to the +x axis.
Explanation / Answer
Here ,
1) mass , m = 3.3 *10^-3 Kg
charge , q = -35 uC
acceleration ,a = 2.37 *10^3 i m/s^2
for the electric field E
Using second law of motion
q *E = m * a
-35 *10^-6 * E = 3.3 *10^-3 * 2.37 *10^3 i
solving for E
E = -2.23 *10^5 i N/C
the electric field is 2.23 *10^5 N/C in negative x direction.
2) Here,
as net electric force is Enet = E1 + E2
Enet = 1387 * (cos(39) i + j * sin(39)) + 1560 * ( cos(57) i + j * sin(57) )
Enet = 1927 i + 2181.2 j
Enet = sqrt(1927^2 + 2181.2^2) at arctan(2181.2/1927) degree
Enet = 2910.6 N/C at 48.5 degree
the magnitude of electric field is 2910.6 N/C and direction is 48.5 degree
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.