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arning.com/ibiscms/mod/ibis/view.php?id 4937272 E Home: K-State Athle L. PlusPortals-Rediker Bramlage Event Staff ilv Kansas State Uni @) 3/12/2018 11:59 PM2.5/10 Print Calaiar Porodic Table Question 5 of 12 Sapling Learning You place a 3.53-mm-high diamond on the axis of and 13.7 am from a lens with focal length-6.41 cnm. If it can be determined, is the diamond's image real or virtual? O Cannot be determined O Real Virtual rkeyy as a Number If it can be determined, is the image upright or inverted with respect to the real thing? O Cannot be determined O Inverted O Upright rch

Explanation / Answer

Given,

h = 3.53 mm ; o = 13.7 cm ; f = -6.41 cm

we know from lens eqn

1/f = 1/i + 1/o

i = o x f/(o - f)

i = 13.7 x -6.41/(13.7 + 6.41) = -4.37 cm

As the image distance is negative:

The image is VIRTUAL.

We know from the defination of magnification:

M = -i/o = h'/h

h' = -(-4.37)/13.7 x 3.53 = 1.126 mm

Hence, h' = 1.126 mm

Since the magnification is POSITIVE:

The image is UPRIGHT.

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