As shown in the figure below, when a charged particle enters a region of magneti
ID: 1585537 • Letter: A
Question
As shown in the figure below, when a charged particle enters a region of magnetic field traveling in a direction perpendicular to the field, it will travel in a circular path. If the magnitude of the magnetic field is 0.200 T, the speed of the particle is 12.0 × 106 m/s, the radius of the trajectory of the path is 105.8 cm, and the charge has a magnitude of 3.20 x 10-19 C, determine the following (a) sign of the charged particle O positive O negative (b) mass of the particle (use the conversion 1 u1.66 x 1027 kg)Explanation / Answer
a) sign of charged particle is positive
b) m v2 / r = B q v
m = B q r / v
= (0.200 * 3.2 * 10-19 * 105.8 * 10-2) / (12 * 106)
= 5.64 * 10-27 kg
= 5.64 * 10-27 kg * u / (1.66 * 10-27)
mass of particle = 3.39 u
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