Black coat color in horses is conferred by the presence of a dominant B allele.

Question

Black coat color in horses is conferred by the presence of a dominant B allele. Chestnut horses are genotype bb. A population of wild horses consists of 129 black horses and 37 chestnut horses. Assume that this population is at Hardy-Weinberg equilibrium for this locus.

Please round all answers correctly to 4 decimal digits.

What is the frequency of the B allele?

What is the frequency of the b allele?

How many horses in the population are expected to be heterozygous for this locus?

Could really use help in this area of Genetics, Much appreciate to all that help

Explanation / Answer

Hardy weinberg equation is p^2+2pq+q^2=1

Black horses are 129

chestnut horses are 37

So recessive allele are bb which are in chestnut horses and the frequency is 37/166 = 0.2229

So q^2 = 0.2229, q= 0.4721

p+q=1

p= 0.5279

Putting these values in the equation

p^2+2pq+q^2=1

0.5279^2+2*0.5279*0.4721*0.4721^2=1

0.2787+0.4984+0.2229 = 1

Answers to the questions

1. Frequency of B allele is :- 0.5279 it means approx 53 out of hundred

2. Frequency of b allele is :- 0.4721 it means approx 47 out of humdred

3. The frequency for hetrozygous are 0.4984 it means approx 50 out of hundred, so in a population of 166 , 83 will be hetrozygous.

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