For the question below, why is the mass of aluminum 27grams when you plug it int

Question

For the question below, why is the mass of aluminum 27grams when you plug it into the equation n=(6.02*10^23) / (mass/density) ??? Also, why are we using avogadro's number here??

I DONT NEED THE ANSWER TO THE QUESTION BELOW, I JUST NEED A CONCEPTIONAL UNDERSTANDING AS TO KNOW WHY THE FORMULA FOR "N" WORKS AND WHERE DOES THE NUMBERS FOR MASS AND AVOGADROS NUMBER COME FROM IN THE QUESTION. THANKS!!!

An aluminum wire having a cross-sectional area of 5.30 × 10-6 m2 carries a current of 3.50 A. The density of aluminum is 2.70 g/cm3. Assume each aluminum atom supplies one conductlon electron per atom. Flnd the drift speed of the electrons In the wire. 0685 mm/s Need Help? Read It

Explanation / Answer

As you have already done the problem and you say you donot need the answer I am only going to give the explanation to your two questions.

Here, n = number of electrons per unit volume

Now one atomic mass of an atom contain = 6.023*10^23 atoms, so, n = 6.023*10^23/volume of one atom

= 6.023*10^23/atomic mass/density

For aluminium, atomic mass = 27gm

I think your doubts are cleared.

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