mon/TakeTutorialA nt.aspx CAS-Central Authen My Dashboard-Uni 0Home- UCONNECTC M

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mon/TakeTutorialA nt.aspx CAS-Central Authen My Dashboard-Uni 0Home- UCONNECTC M McGraw Hill Connect (23%) Problem 4: A wire of length L = 0.85 m and mass m = 0.095 kg carries a current of! 0.25 A. The wire is floating at rest in a magnetic field as shown in the figure. L= 0.85 m m 0.095 kg I= 0.25 A Otheexpertta.com 25% Part (a) What are the forces acting on the wire, and which directions do they go? Grade Summary OGravity, downward. Magnetic force, upward Magnetic force, upward. Gravity, upward Gravity, upward. Magnetic force, dowaward Magnetic force, downward Gravity, downward Potential 100% Submissions Attempts remaining CL-per attempt) detailed viesw Submit Hint i give up! Feedback: deduction per feedback. Hints:·0% deduction per hint Hints remainin. 25% Part (b) Express the rnagnitude of the magnetic force in terms of the current 1, length L and the magnetic field B 25% Part (c) Given the fact that the wire is floating at rest, derive an expression for B 25% Part (d) Calculate the numerical value of B in tesla. o e

Explanation / Answer

Solution:

a) Using right hand rule Magnetic force will be upward and Gravity will be downward.

So option a) gravity downward, Magnetic force, upward will be right

b) Force on a current carrying conductor placed in a magnetic field is given by,

=> F = ILBsin

Here sin  = 1

=> F = ILB

c) Given that the wire is floating implies that gravitational force is equal to magnetic force.

=> mg = ILB

=> B = mg / IL

d) Substituting the given values, we get

=> B = 0.095 x 9.8 / 0.25 x 0.85

=> B = 4.38 T (approx)

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