help please (20 POINTS) 9.) Due to its immense size (and the corresponding press

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help please

(20 POINTS) 9.) Due to its immense size (and the corresponding pressures and t deuterium. H , and tritium, , into helium.and anexces below. Suppose the mass of deuterium is given by mo, the mass of tritium is given by nr helium is given by me, and the mass of a neutron is given by mn temperatures) a star can fuse He, and an excess neutron through the process described a.) In terms of the variables for the masses provided and fundamental expression for the amount of energy released, E, by this fu b.) Using your expression from part a.,) and the constants below, calculate th energy released, E, in Joules in this fusion reaction. (5 POINTS) Mp = 3.3445 × 10-27 kg M7 5.00827 × 10-27 kg mye = 6.6465 × 10-27 kg mn = 1.67493 × 10-27 kg

Explanation / Answer

Solution:

a) Given Mass of Deuterium = Md

Mass of Tritium = Mt

Mass of helium = Mhe

Mass of neutron = Mn

To find the expression for energy released Using E = mc^2

Here m is called mass defect and m = mass of reactant - mass of product.

=> m = ( Md + Mt) - ( Mhe + Mn)

So final expression for energy released would be

=>  E = ((Md + Mt) - (Mhe + Mn)) c^2

b) Substituting the given values we get,

=> E =  ((3.3445 + 5.00827) - (6.6465 + 1.67493)) x 9 x 10^16 x 10^-27

=> E = 0.28206 x 10^-11 J

=> E = 2.8206 x 10^-12 J

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