AT&T; LTE 7:32 PM blackboard.kean.edu A proton of mass 1.67 x 1027 kg and charge

Question

AT&T; LTE 7:32 PM blackboard.kean.edu A proton of mass 1.67 x 1027 kg and charge 1.6 x 1019 C enters a velocity selector of magnetic field of 0.4 T. If we want the proton to have a velocity of 5x105 m/'s when it comes out of the selector, what must be the electric field of the selector? 12 x 10%N After coming out of the chamber in question #1 with a velocity of 5 x 105 m/s the proton enters a mass spectrometer with a magnetic field of O.4 T. What will be the radius of it's motion? A wire carried a current of 5 A. What is the value of the magnetic field at pt P 50 cm away from the wire alone. 03x10 What is the total magnetic field at pt P due to both wires? 01310 46710 86710 QUESTION

Explanation / Answer

1)2 x 10^5 N/C

explanation:

We know that

E/B = v => E = BV

E = 0.4 x 5 x 10^5 = 2 x 10^5 N/C

Hence, E = 2 x 10^5 N/C

2)0.013 m

expalantion:

R = mv/Bq

R = 1.67 x 10^-27 x 5 x 10^5/(0.4 x 1.6 x 10^-19) = 0.013 m

Hence, R = 0.013 m

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