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question 7 WebAssign e Chegg Study | Guide. VHL Central | activitie + WebCOMTM 2

ID: 1584620 • Letter: Q

Question

question 7

WebAssign e Chegg Study | Guide. VHL Central | activitie + WebCOMTM 2.0 HW#8 Reik-Me Niego ft.0 Secure https://www.webassign.net/web/Student/Assignment-Responses/submit?dep- 17876965 ::: Apps America- a , D UCF login D Cengage . WebAssign Mathway l Math Pro. VHL Central I Course WebCOM™ 2.0 -Imported From IE -Other Bookmarks A This page is in EnglishWould you like to translate it? Nope Translate Never translate English OptionsX Need Help? Watch It 7. 0.6/3 points | Previcus Answers SerPSES B.P014.MI.FB My Notes Ask Your A crate of mass 10.2 kg is pulled up a rough incline with an initial speed of 1.60 m/s. The pulling force is 104 N parallel to the incline, which makes an angle of 19.0° with the horizontal. The coefficient of kinetic friction is 0.400, and the crate is pulled 5.04 m. (a) How much work is done by the gravitational force on the crate? -7S.5 How is the work done by gravity related to the gravitational potential energy of an object? J (b) Determine the increase in internal energy of the crate-incline system owing to friction. 199.2 The normal force is not equal to mg. Draw a careful free-body diagram of the crate. (c) How much work is done by the 104-N force on the crate? 524.16 (d) What is the change in kinetic energy of the crate? 249.46 You appear to have calculated the change in kinetic energy correctly using your incorrect results from the previous parts. J (e) What is the speed of the crate after being pulled 5.04 m? 7.17 You appear to have calculated the speed correctly using your incorrect result from part (d). m/s Need Help? Master t 8. 0/2 points | Previous Answers SerPSE9 8.P025.MI. My Notes Ask Your Teacher A 235-g block is pressed against a spring of force constant 1.35 kN/m until the block compresses the spring 10.0 cm. The spring rests at the bottom of a ramp inclined at 60.0° to the horizontal. Using energy considerations, determine how far up the incline the block moves from its initial position before it stops under the following conditions. (a) if the ramp exerts no friction force on the block

Explanation / Answer

7)

a) Workdone by gravity = -m*g*d*sin(theta)

= -10.2*9.8*5.04*sin(19.0)

= -164 J

b) Increase thermal energy = -Workdone by friction

= -(fk*d*cos(180))

= fk*d

= mue_k*N*d

= mue_k*m*g*cos(theta)*d

= 0.4*10.2*9.8*cos(19)*5.04

= 190.5 J

c) Wokdone by applied force = F*d*cos(0)

= 104*5.04*1

= 524.16 J

D) change in kinetic energy = Net Workdone

= W_gravity + W_friction + W_applied force

= -164 - 109.5 + 534.16

= 260.7 J

E) KEf - KEi = 260.7

KEf = 260.7 + KEi

(1/2)*10.2*vf^2 = 260.7 + (1/2)*10.2*1.6^2

==> vf = 7.32 m/s