Q6 and Q7 Q6 and Q7 5) Two capacitors are first connected in series to a potenti
ID: 1584039 • Letter: Q
Question
Q6 and Q7 Q6 and Q7 5) Two capacitors are first connected in series to a potential source·The charged capacitors are then removed from the source and connected to each other such that the positive plate of the first capacitor is connected to the positive plate of the second capacitor. Determine the final potential across the first capacitor long after the switch is closed. CI 6) Two capacitors are first connected in series to a potential source E. After static equilibrium occurs, a capacitor is connected as shown. An ammeter is used to measure the current flowing through the switch. After the switch is closed. charge is redistributed. Determine the total charge that flows through the ammeter long after the switch is closed. Ct CA C, 7) Two capacitors are first connected in series to a potential source E. After static equilibrium occurs, a third capacitor is connected as shown. An ammeter is used to measure the current flowing from the source. After the switch is closed, charge is redistributed. Determine the total charge that flows through the ammeter long after the switch is closed. C, 8) Two capacitors are first connected in series to a potential source E. After static equilibrium occurs, a wire is connected as shown. An ammeter is used to measure the current flowing from the source. After the switch is closed, charge is redistributed. Determine the total charge that flows through the ammeter long after the switch is closed.Explanation / Answer
5.
C1 and C2 are in inittially is series and their combination is given as
Cs = C1 C2/(C1 + C2)
charge stored by each capacitor in series is given as
Q = Cs E = C1 C2 E/(C1 + C2)
when capacitors are connected in parallel , lets assume the charge on them is Q1' + Q2'
using conservation of charge
Q1' + Q2' = 2Q = 2 C1 C2 E/(C1 + C2) eq-1
also
Q'1/C1 = Q2'/C2
Q'1 = (C1 /C2) Q2' eq-2
using eq-1 and eq-2
Q1' + Q2' = 2 C1 C2 E/(C1 + C2)
(C1 /C2) Q2' + Q2' = 2 C1 C2 E/(C1 + C2)
Q2' = 2 C1 C22 E/(C1 + C2)2
using eq-2
Q'1 = (C1 /C2) Q2' = (C1 /C2) (2 C1 C22 E/(C1 + C2)2 )
Q'1 = 2 C21 C2 E/(C1 + C2)2
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