iPad, 12:23 PM * 29%. PHY 201-01/03 Basic Physics Homework 3 Due: March 5, 2018
ID: 1583847 • Letter: I
Question
iPad, 12:23 PM * 29%. PHY 201-01/03 Basic Physics Homework 3 Due: March 5, 2018 Name: Student ID: (20 Points) Problem An object is moving at 6 mis along x-direction. An acceleration of 1.5 m/s? is applied on the object in the y-direction only 0.e, there is no acceleration in he x-direction) Find (a) the x- and the y- component of velocity of the object after 4 seconds, and (b) the magnitude of displacement after that time. Problem 2 (20 Points) From a point on level ground, an object is thrown with an initial velocity of 40 m's at an angle of 35 with the horizontal (a) What is the maximum height the object will rise? (b) What is the maximum horizontal distance (the range) the object will travel? (e) At what horizontal distance(from the point of projection) the object will attain a height of 10 m? (d) What is the height of the object at a horizontal distance of 60 m? (20 points) Problem 3 You throw a ball towards a wall with a speed of 25 m/s and at an angle of 8-40 above the horizontal The wall is at a distance of 22 m from the release point of the bal. (a) How far above the release point does the ball hit the wall? (b) What aro the (i) horontal and (i) vertical components of its velocity as it hits the wal? Problem 4 A boy whirls a stone in a horizontal circle of radius 0.75 m and at a height of 1.5 m above level ground The string breaks, and the stone flies off horizontally and strikes the ground after traveling a horizontal distance of 4 m. What is the magnitude of centripetal acceleration of the stone during the circular motion? (20 Points) Problem (20 Points) A fan is rotating at 90 rpm. The tip of a blade is 0.25 m from the center of the fan. Find (a) distance the tip moves in one revolution, (b) speed of the tip. (c) acceleration of the tipand(d) period of the motion.Explanation / Answer
Only one question can be posted as per chegg guidelines
1.
a)
Given Vox=6 m/s
Voy=0
and ay=1.5 m/s2 and ax=0
From
V=V0+at
at t=4 s
Vx=6+0=6 m/s
Vy=0+1.5*4 =6 m/s
b)
Horizontal displacement in t=4 s is
X=Vxt =6*4=24 m
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