omework 5 Begin Date: 2/15/2018 12:00:00 AM-Due Date: 3/772018 11:59:00 PM End D

Question

omework 5 Begin Date: 2/15/2018 12:00:00 AM-Due Date: 3/772018 11:59:00 PM End Date: 37 2018 11.39:00 PM (656) Problem 9: A rock of mass m-0.51 kg is attached to a massless string of length L- a.52 m. The rock is swung in a vertical circle faster and faster up to a speed of v 3.3 m/s, at which time the string breaks. This occurs when the string is horizontal "is shown in the figure. Break Otheexpertta.co 50% Part (a) what is the magnitude of the tension, in newtons, at which the string breaks? Grade Summary Deductions Potential 100 sinO cotanasin0 atano tan) acoso Submissions Attempts remaining (0% per attempt) detailed view coso acotano sinh0 tanho cotanho ODegrees Radians Submit I give up! Hints: 2% deduction per hint. Hints remaining:- Feedback: 2%deduction per feedback Submission History Answer Hints Feedback Tota Totals 0% - 50% Part (b) How high, in meters, does the rock travel? Use a value of h-0 at the location of the break

Explanation / Answer

Ans)

Given that mass m=0.51kg,

Length L=0.52m,

Speed v=3.3m/s.
part a)

As the tension in the string is greatest at the bottom when the string is vertical this is the most likely place at which the string will break.
At the point specified F = (m v2) /r
=(0.51x3.3x3.3)/(0.52)

=(5.5539)/(0.52)

=10.68N
part b)

To find the height Ek = mgh
but Ek = 1/2 mv2
1/2 mv2 = mgh
h = v2 / ( 2g)
=(3.3x3.3)/(2x9.8)

=0.55m

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