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3. 0/2 points I Previous Answers SerCP10 20 P.006 My Notes Ask Your Teac A 440 t

ID: 1583619 • Letter: 3

Question

3. 0/2 points I Previous Answers SerCP10 20 P.006 My Notes Ask Your Teac A 440 turn solenoid of length 30.5 cm and radius 3.10 cm carries a current of 5.10 A. Find the following. (a) the magnetic field strength inside the coil at its midpoint 8.06 Your response differs from the correct answer by more than 10%. Double check your calculations. mT (b) the magnetic flux through a circular cross-sectional area of the solenoid at its midpoint 0.024 Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. T m2

Explanation / Answer

a) N = 449

L = 0.305 m

r = 3.1 cm = 0.031 m

I = 5.1 A

for the magnetic field

magnetic field = u0 * N * I/L

magnetic field = 4pi *10^-7 * 440 * 5.1/(0.305)

magnetic field = 9.24 * 10-3 T

magnetic field = 9.24 mT

b) magnetic flux = magnetic field * area

magnetic flux = 9.24 *10^-3 * pi * 0.0310^2

magnetic flux = 2.78 *10-5 T.m^2

the magnetic flux is 2.78 *10-5 T.m^2

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