2. A charged particle moves through a constant magnetic field. The magnetic forc
ID: 1583595 • Letter: 2
Question
2. A charged particle moves through a constant magnetic field. The magnetic force on this particle: A. increases the particle's kinetic energy whatever the sign of the charge. B. increases the KE of the particle if its charge is positive and decreases the KE of the particle if its charge is negative. C. is in the direction of motion of the particle. D. does not influence the kinetic energy of the particle. E. is independent of the speed of the particle whatever the direction of motion. 3. An electron is moving vertically upward at 2.0 x 108 m/s in a magnetic field of 1.0 T directed toward the east. The magnetic force on the electron is: A. 2.0 x 108 N north D. 2.0 x 108 N south G. 3.2x 10-11 N vertically up B. 2.0 x 108 N east E. 3.2 × 10-11 N north H. 3.2 × 10-11 N south C. 2.0 × 108 N vertically up F. 3.2 × 10-11 N to the west 4. A proton (positively charged hydrogen nucleus) has an initial north-directed velocity, but is observed to curve toward the east as a result of a magnetic field B. The direction of B is: A. to the east. B. to the west. C. downward, into the paper. D. upward, out of the paper. E. to the north F. to the south.Explanation / Answer
2. if the charged particle moves throuh a constant magnetic fiel. The magnetic force on this particle is given by
F = q(VXB) = qvB sin theta
says the force acting on the particle
the kinetic energy is k.e = 0.5*m*v^2
as the field is constant then the constant force acts on it results , it does not influence the kinetic energy fo the particle.
option C is answer
3.
electron moving upward with v = 2*10^8 m/s
magnetic field is B = 1.0 T to the east
the magnetic force is F = q(VXB) = qvB sin theta
theta is the angle between the v and B is 90 degrees now
F = 1.6*10^-19*2*10^8*1 sin 90 T = 3.2*10^-11 T
directed by right hand rule ==> south
answe is optin H
4.
by right hand rule the direction of the magnetic field is to the east so that the force is into the page
answer is option A
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