An air filled capacitor consists of two parallel plates each with an area of10 c

Question

An air filled capacitor consists of two parallel plates each with an area of10 cm^3 separated by distance of 2.0 mm. A 5V potential difference is applied to these plates. Calculate
a). The magnitude of the electric field between the plates b). The surface charge density c). The capacitance d). The magnitude of the charge on each plate.
An air filled capacitor consists of two parallel plates each with an area of10 cm^3 separated by distance of 2.0 mm. A 5V potential difference is applied to these plates. Calculate
a). The magnitude of the electric field between the plates b). The surface charge density c). The capacitance d). The magnitude of the charge on each plate.
An air filled capacitor consists of two parallel plates each with an area of10 cm^3 separated by distance of 2.0 mm. A 5V potential difference is applied to these plates. Calculate
a). The magnitude of the electric field between the plates b). The surface charge density c). The capacitance d). The magnitude of the charge on each plate.

Explanation / Answer

given

A = 10 cm^2 = 10*10^-4 m^2

d = 2 mm = 2*10^-3 m

V = 5 V

a) E = V/d

= 5/(2*10^-3)

= 2500 N/c

b) we know, E = sigma/epsilon

==> sigma = E*epsilon

= 2500*8.854*10^-12

= 2.21*10^-8 C/m^2

c) C = A*epsilon/d

= 10*10^-4*8.854*10^-12/(2*10^-3)

= 4.43*10^-12 F

d) Q = C*V

= 4.43*10^-12*5

= 2.22*10^-11 C

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.