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5. A 4220-kg satellite is in a circular earth orbit that has a radius of 3370000

ID: 1583424 • Letter: 5

Question

5. A 4220-kg satellite is in a circular earth orbit that has a radius of 3370000 m. An xternal force acts on the satellite to take it to a higher circular orbit that has a radius of 960000 m. What work does the external force do? (Hint: Remember that the speed of a satellite on a circular orbit is uniquely defined by the radius of the orbit) -8.00 x 10°J) 10 You throw a small rock (m = 85.0 g) from the top of a building at a speed of 8.40 m/s. The building is 27.0 m tall. Ignoring air resistance, find the speed with which the rock strikes the ground when the rock is thrown (a) horizontally, (b) vertically straight up, and (c) vertically straight down. (24.5 m/s, 24.5 m/s, 24.5 m/s) 8 11. A 46.0-g golf ball is driven from the tee with an initial speed of 47.2 m/s and rises to at its highest point. (b) What is its speed when it is 6.30 m below its highest point? (41.8 J, a height of 21.0 m. (a) Neglect air resistance and determine the kinetic energy of the ball 0 44.0 m/s) 12. A small ball, starting from point A in the drawing (the height at A above the flour is 2.00 m), is projected down the curved runway. Upon leaving the runway at point B, the ball's velocity is directed straight upward and the ball reaches a height of 3.82 m above the floor before falling back down. Ignoring friction and air resistance, find the speed of he ball at point A. (5.97 ms) 6

Explanation / Answer

According to the chegg guidelines I am allowed to answer only 1 question at a time.

1) M(s) = 4220 KG

R = 3.37 * 10 ^ 6 M

D = 4960000 M

Work done = 1/2 * G * M(m) * ( 1./r1 - 1/r2 )

Work done = 0.5 * 6.673 * 10 ^ -11 * 4220 * 5.98 * 10 ^24 * ( 1/4960000 - 1/3370000 )

Work done = -8.009221621 * 10 ^ 10 Joule==============ANSWER)

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