Introduction to Moments of Inertia and Rotational Kinetic Energy 1 of 11 > Part

Question

Introduction to Moments of Inertia and Rotational Kinetic Energy 1 of 11 > Part F Constants | Periodic Table Using the total moment of inertia Iy of the system found in Part E, find the total kinetic energy K of the system Express your answer in terms of m, a, and r Learning Goal To understand the definition and the meaning of moment of inertia; to be able to calculate the moments of inertia for a group of particles; to relate moment of inertia to kinetic energy By now, you may be familiar with a describing rotational kinematics. One thing that you mav have noticed was the similarity hetween set of e quations Figure 1 of 1 SubmitPrev Previous Answers Request Answer Incorrect, Try Again: 4 attempts remaining Part G This question will be shown after you complete previous question(s) 3r Part H This question will be shown after you complete previous question(s). PartI This question will be shown after you complete previous question(s)

Explanation / Answer

Solution:

Using the formula of Kinetic energy = 1/2 mv^2 and v = r w ( w is angular velocity i.e omega)

=> Kinetic energy of particle a = 1/2 m x (3r)^2 x w ^2

=> K.E_a = 9 m w^2 r^2 / 2

Similarly Kinetic energy of particle b

=> K.E_b = m w^2 r^2 / 2

Total kinetic energy of the system K.E = 11 m r^2 w^2 / 2

K.E = 11m²r² / 2

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