01-1 ps://edugen wileyplus.com/edugen/ti/main.uni Halliday, Fundamentals of Phys

Question

01-1 ps://edugen wileyplus.com/edugen/ti/main.uni Halliday, Fundamentals of Physics, 10e PRIN TE R VERSION | BACK Chapter 10, Problem 034 The figure gives angular speed versus time for a thin rod that rotates around one rotational kinetic energy of 9.52 J. What is its kinetic energy at t - o7 end. (a) what is the magnitude of the rod's angular acceleration? (b) At t-4 0 s the rod has a r (s) (a) Number (b) Number Units SHOW HINT LINK TO TEXT LINK TO SAMPLE PROBLEM VIDEO MINT LECTURE Question Attempts: o of 6 used sve rOR LATERSDNITAW

Explanation / Answer

a)
In 4 seconds its angular velocity increases from -2rad/s to 4 rad/s
Angular acceleration = d/dt
= (f - i) / dt
= (4 - (-2)) / 4
= 6/4 rad/s²
= 1.5 rad/s²

b)
At t = 4 s
= 4 rad/s
K = 9.52 J

At t = 0
= -2 rad/s
K = ?

Rotational kinetic energy (angular velocity)²
K/K = (/)²
9.52J / K = ((4 rad/s) / (-2 rad/s))²
K = 9.52J / 4
K = 2.38 J

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