Problem 2 A rectangular loop with a length of 0.600 m, width of 0.400 m, and con

Question

Problem 2 A rectangular loop with a length of 0.600 m, width of 0.400 m, and consisting of 187 tightly-wrapped turns is hinged along the y-axis and placed in a uniform magnetic field such that the plane of the loop makes an angle of 35.0° with the r-axis (see figure below). The magnetic field has a magnitude of 0.810T and points in the positive z direction, and the current in the coil is 1.25A. Top view nasA 35.0 0.60 m 35.0° 2 0.40 m (a) Determine the magnitude of the torque exerted on the loop (b) Determine the expected direction of rotation of the loop, as viewed from above.

Explanation / Answer

(a)We know that the torque in magnetic field id given by:

Torque = N I B A sin(theta)

N = 187 ; I = 1.25 A ; B = 0.810 T ; theta = 35 deg

A = 0.6 x 0.4 = 0.24 m^2

Torque = 187 x 1.25 x 0.810 x 0.24 x sin35 = 26.064 N-m

Hence, Torque = 26.064 N-m

(B)The loop will rotate in counter clockwise direction as seen from above.

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