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10. [1pt] In the picture below, the two wires carry current i and i2, respective

ID: 1583260 • Letter: 1

Question

10. [1pt] In the picture below, the two wires carry current i and i2, respectively, with positive current to the right. The charge q is positive and has velocity v to the right. (It is midway between the two wires, as shown) ("North" is up the page, "East" is right, and so on.) For the statements below, select T-True, F-False. If the first is T and the rest F, enter TFFFF. A) If v-0, then the force on q is zero B) If ii is greater than i2, then the force on q is north C) If ii2, then the force on q is zero D) If 12 = 0 and 11 is greater than zero, then the force on q is north E) If i2, then the wires repel cach other. FIi0 and i2 is greater than zero, then the magnetic field near charge q points out of the page.

Explanation / Answer

A) true , F= qvB , v= 0 so F= 0

B)True, The field due to I1 is going inside and field due to I2 is coming outside

using right-hand rule the force due to I1 will be in the north and due to I2 will be towards the south. So If I1 is more than I2 resultant force will be in the north.

C) false, If I1 = -I2 that means both currents are in opposite direction i.e I2 is in east and I1 is in west direction

The field due to I1 is coming outside and field due to I2 is also coming outside

using right-hand rule the force due to I1 will be in the south and due to I2 will be towards the south. So both the forces are in the same direction so they add

D) True, If I2 = 0, then force will be due to I1 only

The field due to I1 is going inside using right-hand rule the force due to I1 will be in the north

E)True, when currents are in opposite direction wires repel each other.

F)True, If I1 = 0, the field will be due to I2 only and field due to I2 is coming outside

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