Question: A 0.100 kg ball is pitched towards a batter, and has a horizontal velo

Question

Question: A 0.100 kg ball is pitched towards a batter, and has a horizontal velocity of 5.00 m/s just before the batter hits it. Just after the hit, the ball is traveling at 10.0 m/s horizontally in the opposite direction. The magnitude of the impulse that the bat applied to the ball is a. 15N.S b. 0.50Ns c. unknown; we would need to know the Force that was applied to the ball d. unknown; we would need to know the time that the bat was in contact with the ball e unknown; we would need to know both the Force applied and the time of contact ©2014, Richard White. LearnAPphysics.com

Explanation / Answer

Initial momentum = 0.1×5 = 0.5 kg-m/s

Final momentum = 0.1×(-10) = -1 kg-m/s

So change in momentum = (-1-0.5) = -1.5 kg-m/s = -1.5 N•s

This is the impulse that ball applies on batter.

So the impulse applied by batter to the ball = 1.5 N•s

So option a is correct

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