Please show detail and explain 4. A negatively charged particle is moving betwee

Question

Please show detail and explain

4. A negatively charged particle is moving between two current-carrying straight wires at a constant velocity as shown right. (Note: both the currents and the motion of the charge are on a same plane in the figure.) d 2136.0" q =-79.5 mC , v = 345.0 km/s 11 = 1.5 A, di = 1.2mm , 12-2.0A. d2= 2.3mm di Find the magnitude and the direction of the total magnetic field due to these currents at the location of the charge. (a) (b) What is the magnitude and the direction of the magnetic force on the charge?

Explanation / Answer

4)

a) at the location of the charge both wires produce magnetic field in to the page.

Bnet = B1 + B2

= mue*I1/(2*pi*d1) + mue*I2/(2*pi*d2)

= 4*pi*10^-7*1.5/(2*pi*1.2*10^-3) + 4*pi*10^-7*2/(2*pi*2.3*10^-3)

= 4.24*10^-4 T

direction : into the page

b)

magnitude of frce acting on the charges paarticle, F = q*v*Bnet*sin(theta)

= 79.5*10^-3*345*10^3*4.24*10^-4*sin(90)

= 11.6 N

direction : parallel to I2

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.