Pease show all work. Rate will be given once answers are confirmed to be correct

Question

Pease show all work. Rate will be given once answers are confirmed to be correct.

A uniformly charged insulating rod of length 22.cm is bent into the shape of a semicircle, as shown. The rod has a total charge of-12-LO. Find the magnitude and direction of the electric field at the center of the semicircle (that is, the center of the circle that contains the semicircle). [SJ E07 23.27] 15. Magnitude a. 20720000 N/Cd. 8032000 N/C b. 18480000 N/Ce. 22870000 N/C f.23740000 N/C c. 14020000 N/C 16. Direction a. C. b. d.

Explanation / Answer

here,

length of rod , l = 22 cm = 0.22 m

the radius of circle , r = l/pi

total charge , Q = - 12 uC = 12 * 10^-6 C

a)

the magnutude of electric feild at the center , E = 2 * k * lamda /r

E = 2 * k * ( Q/L) /r

E = 2 * 9 * 10^9 * ( 12 * 10^-6 /0.22) /( 0.22/pi)

E = 1.4 * 10^7 N/C

the magnitude of electric feild is c) 14020000 N/C

b)

the direction is b)

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