A farmer is pulling a watering trough out to the cows in his field using a tract
ID: 1582546 • Letter: A
Question
A farmer is pulling a watering trough out to the cows in his field using a tractor. The trough is attached to the tractor by a chain of constant length. The trough is sliding across the rather muddy ground.
The mass of the trough is 397.9 kg, the mass of the tractor is 974.4 kg, and mass of the chain is 27.2 kg.
The frictional force between the trough and the ground is 1/4 the weight of the trough (gravitational force).
If the tractor accelerates at 0.43 m/s2, what is the magnitude of the total horizontal (frictional) force that the tractor is exerting on the ground? ("Magnitude" means your answer is positive.)
Explanation / Answer
here,
mass of trough , m1 = 397.9 N
the mass of tractor , m2 = 974.4 kg
mass of chain , m3 = 27.2 kg
accelration , a = 0.43 m/s^2
the magnitude of the total horizontal force that the tractor is exerting on the ground, F = (m1 + m2 + m3) * a + frictional force
F = (m1 + m2 + m3) * a + m1 * g/4
F = ( 397.7 + 974.4 + 27.2) * 0.43 + 397.9 * 9.81 /4 N
F = 1577.5 N
the magnitude of the total horizontal force that the tractor is exerting on the ground is 1577.5 N
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