004 (part 1 of 3) 10.0 points A device (\"source\") emits a bunch of charged ion

Question

004 (part 1 of 3) 10.0 points A device ("source") emits a bunch of charged ions (particles) with a range of ve- locities (see figure). Some of these ions pass through the left slit and enter "Region I" in which there is a vertical uniform electric field (in the -j direction) and a 0.2T uniform mag- netic field (aligned with the k-direction) as shown by the shaded area. +1000 V Region of Magnetic Field 0.2 T 1.3 cm -Region I- Region II Figure: i is in the direction +r (to the right), j is in the direction +y (up the page), and k is in the direction +z (out of the page). In which direction (relative to the coordi- nate system shown) should the magnetic field point in order for negatively charged ions to move along the path shown by the dotted line in the diagram? 2. IIB = 0 ; direction undetermined IB 5 (ont of 3) 10.0 points

Explanation / Answer

According to the concept of the moving charges in magnetic field

Emf=BLv

The direction of the magnetic field point is +K direction

Given that

Electric potential E=1000 v

Length L=1.3 cm

Magnetic field B=0.2 T

Now we find the speed of the single charged ion

E=BLv

1000=0.2*1.3*10^-2*v

Speed v=3.85*10^5 m/s

Now we find the mass of the ion

Mass =Bqr/v=0.2*7*10^-18*0.58/3.85*10^5=0.211*10^-23

=2.11*10^-24 kg

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