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What is the net force exerted by these two charges on a third charge q 3 = 45.0

ID: 1582451 • Letter: W

Question

What is the net force exerted by these two charges on a third charge q3 = 45.0 nC placed between q1 and q2 at x3 = -1.215 m ?

Your answer may be positive or negative, depending on the direction of the force.

Express your answer numerically in newtons to three significant figures.

Thank you in advance

Coulomb's law for the magnitude of the force F between two particles with charges Q and Q separated by a distance d is d2 where K-4160 , and Co 8.854 × 10-12 c2/(N-m2) is the permittivity of free space. Consider two point charges located on the x axis: one charge, 9110.0 nC, is located at 1-1.740 m; the second charge, 92-32.0 nC is at the origin (z 0.0000)

Explanation / Answer

The force due to a charge particle on another charged particle is given by

F = k*q1q2/r^2

or F = force due to q1 + force due to q2

= 9*10^9*(10^-8)*45*10^-9/(1.74-1.215)^2 + 9*10^8*32*10^-9*45*10^-9/1.215^2

=1.55*10^-5 N (towards the negative x axis)

=-1.55*10^-5 N

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