A converging lens has a focal length f = 11.2 cm. Locate the images image distan

Question

A converging lens has a focal length f = 11.2 cm. Locate the images image distance in cm for the ob ect ditances given below. For each case state whether the image is real or virtual and upright or inverted, and find the magnification. (If no image forms, or forms at infinity, enter INFINITY for the image distance and DNE for the magnilfication. Indlude the sign of the image distance and magnification.) (a) 22.4 image distance image orientation-Select magnification (b) 11.2cm image distance image orientation magnification Solect (c) 5.6 cm image distance image orientationSelect magnification cm Need Help?Boadis

Explanation / Answer

(a) F = 11.2 cm, d0 = 22.4

the thin lens equation

1/f = 1/do + 1/di

where do = object distance and di = image distance

Objects located within the focal point for converging lenses will produce virtual upright images. in fact if you plug in the value

1/11 = 1/22.4 + 1/di

di= 21.61 cm

you will see that the di = Positive
if the object is located outside of the focal point it will produce a real inverted object. plug into the equation. the image distance should be positive  

(b)A converging lens has a positive focal length and will refract light

If the object is at the focal point no image will exist

Here's a setup

(c) F = 11.2 cm, d0 = 5.6

plug in the value
1/f = 1/do + 1/di
1/11 = 1/5.6 + 1/di
di = -61.6/5.4
you will see that the di = negative (indicating a virtual image)

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.