Please help solve part C of practice it and part A and B of the exercise, will g

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Please help solve part C of practice it and part A and B of the exercise, will give good rating!
Please help solve part C of practice it and part A and B of the exercise, will give good rating!

PRACTICE IT Use the worked example above to help you solve this problem. A woman of mass m = 56.7 kg sits on the left end of a seesaw-a plank of length L -4.42 m, pivoted in the middle as shown in the figure. (a) First compute the torques on the seesaw about an axis that passes through the pivot point. Where should a man of mass M-73.8 kg sit if the system (seesaw plus man and woman) is to be balanced? 1.69 (b) Find the normal force exerted by the pivot if the plank has a mass of mpl = 13.3 kg 1409.24 (c) Repeat part (a), but this time compute the torques about an axis through the left end of the plank. EXERCISE HINTS: GETTING STARTED IM STUCK! Suppose a 29.3-kg child sits 1.37 m to the left of center on the same seesaw as the problem you just solved in the PRACTICE IT section. A second child sits at the end on the opposite side, and the system is balanced. (a) Find the mass of the second child (b) Find the normal force acting at the pivot point. Need Help? Talik to s Tutor

Explanation / Answer

c) The torque about the axis passing through the left end has to be zero

Force at the pivot =( 73.8+56.7)*9.8=1278.9 N

Let the distance where 73.8 kg person should be sitting be d from the left end. For the torques to be balanced,

1278.9*4.42/2 = 73.8*9.8*d

d=3.91 m from the left end = 1.69 m from the center (the answer is same as part a of Practice It)

a)From torque balancing,we get

29.3*1.37 = m*4.42/2

m=18.16 kg

b)Normal force acting on the pivot = (29.3+18.16+13.3)*9.8=595.45 N

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