(D) Sketch and label 8 electric field lines for the iron nucleus. HINT: what is
ID: 1582045 • Letter: #
Question
(D) Sketch and label 8 electric field lines for the iron nucleus. HINT: what is the relationship between the equipotential surface and electric field lines?
(E) Suppose we now put a proton, initially at rest, at the inner equipotential. what is the speed of the proton when it reaches the outer equipotential? HINT: Use energy conservation.
(F) Could you use the equations for uniformly accelerated motion, shown below, to solve part (E)?
vxf-vxi+axt
vx^2= vxi^2+2ax(xf-xi)
Your Name (Print) Group Members: Date: Group Energy Conservation: Proton in the Non-uniform Electric Field of an Iron Nucleus Consider a proton (mass 1.67 x 107 kg, gproton te) in the potential field of an iron nucleus (mass-9.40 x 10-26 kg, qrn-+ 26e). Three equipotential surfaces are shown in the diagram as dashed circles; the equipotential lines are NOT equally spaced. Treat the iron nucleus as a point charge. a) Calculate the radial distance from the iron nucleus at which the electric potential is 5.00 Volts. b) Calculate the radial distance from the iron nucieus at which the electric potential is 3.00 Volts c) Calculate the radial distance from the iron nucleus at which the electric potential is 1.00 Volts Label these three equipotential surfaces in the above diagram. PHYS-112 College Physics II Activities Manual Page 101 of 278Explanation / Answer
a) use, V = k*Q/r
==> r = k*Q/V
= 9*10^9*26*1.6*10^-19/5
= 7.49*10^-9 m
b) use, V = k*Q/r
==> r = k*Q/V
= 9*10^9*26*1.6*10^-19/3
= 1.25*10^-8 m
c) use, V = k*Q/r
==> r = k*Q/V
= 9*10^9*26*1.6*10^-19/1
= 3.74*10^-8 m
d) draw 8 lines radially outward from the surface of the nucleus.
e) Apply conservation of energy
U1 + K1 = U2 + K2
U1 + 0 = U2 + K2
K2 = U1 - U2
(1/2)*m*v^2 = q*(V1 - V2)
v = sqrt(2*q*(V1 - V2)/m)
= sqrt(2*1.6*10^-19*(5 - 1)/(1.67*10^-27))
= 2.77*10^4 m/s
F) No. we cants use equation of uniformlay accelerated motion.
because, the force acting on proton is not uniform.
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