(700) Problem! 15: A charge q 5.44E-18 C moves with velocity v = vz k-9500 k m/s
ID: 1582030 • Letter: #
Question
(700) Problem! 15: A charge q 5.44E-18 C moves with velocity v = vz k-9500 k m/s in a uniform electric field E = E, i-95 i V/m and a uniform magnetic field B = By j = 0.45 j T. Refer to the figure Randomized Variables q = 5.44E-18 C B-ByJ = 0.45 j T Otheexpertta.com 17% Part (a) Express the magnitude of the electric force acting on the charge F in terms of E, and Grade Summary Deductions Potential 0% 100% Submissions Attempts remaining:S (2% per attempt) detailed view 0 END DEL CLEAR Submit Hint I give up! Hints: 1 % deduction per hint. Hints r emaining: Feedback: deduction per feedback. 17% Part(b) Calculate the value of FE, in newtons 17% Part (c) what is the direction of the electric force on the charge? -là 17% Part (d) Express the magnitude of the magnetic force, F , acting on the charge in terms of By vz and q 17% Part (e) Calculate the value of FB-in newtons. 1790 Part (f) what is the direction of the magnetic force on the charge? All content © 2018 Expert TALExplanation / Answer
a) F_E = q*Ex
b) F_E = 5.44*10^-18*95
= 5.17*10^-16 N
c) towards +x axis
d) F_B = q*(vz cross By)
= q*vz*By*sin(90)
= q*vz*By
e) F_B = 5.44*10^-18*9500*10^3*0.45
= 2.32*10^-11 N
f) towards -x axis
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.