part C and D Mastering Biology-21E T The Expert TA | 1kman, 1 × x _ : Secure htt

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part C and D

Mastering Biology-21E T The Expert TA | 1kman, 1 × x _ : Secure https://usq45txt HW 4: Forces and applications Begin Date: 2/12/20IS 12:00 00 AM Due Date: 3/2/2018 11:59: 00 PM End Date: 362018 12:00:00 AM (0%) Prollern 17: A golf ball is hit from ground level on a horizontal fairway with initial velocity vector vo - vod+voj. Throughout its trajectory, the golf ball encounters a strong wind which causes the ball to experience an acceleration in the horizoutal direction with a magnitude of 1.45 m's as shown in the figure. Assume that any other air resistarce is negligible. Use a Cartesian coordinate system with the origin at the ball's initial position as shown in Assignment Status Randonized Variables ay1.4Sms Click here for detailed view 25% Part (a) Calculate the maximum heg1st. Asmar in meters, that the ball achieves. e ee 25% Part (b) How long, tro a in seconds, is the ball in the air before it returns to the ground? Problem Status 1 2 Completed Completed 25% Part (d) Calculate the horizontal distance x a in mo e n the ball travels before it return to ground level 4 5 6 Completed Completed Completed Grade Samnary 42.13) 789 HOM 8 Completed 9 Completed 10 Completed 11 Completed 12 Completed 13 Completed 14 Completed 15 Completed cotan) asino acosi atan) ac sinb cotah) e Degrees Radians BACKSPACE CLEAR Sylm I give up Feedback: 2% dedeben prt feedback Hmis: I. for a fr-deduction Hats renuerung You already Lnow the total tai of , andg. frose part 17 Partial Q Type here to search

Explanation / Answer

Let the time of flight be t.so,

t = 2v/g

=2*7.25/9.81

=1.478 s

c)the ball suffers an acceleration of 1.45 m/s^2 in the horizontal direction. Which implies,

x = ut + 0.5at^2

or x(t) = Vox * t + 0.5*Awind*t^2

d)x(t) = 27*1.478 + 0.5*1.45*1.478^2

=41.48 m

If the wind flows as depicted in the figure, then the answer to the question will change.

then the answer will be

c)x(t) = Vxo * t + 0.5*Awind*t^2

d)x = 27*1.478 - 0.5*1.45*1.478^2

=38.322 m

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