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This is optional. Write solutions on this sheet of paper or on a sheet of paper attached to this with your name on it. Show all work in an orderly and legible manner. Use appropriate units and significant figures. Work on this alone. (5 points) which has q2--39 microcoulombs is 10.0 distant from q 1 and is given an initial velocity of 375 m/s directly away from q1. At what distance from q1 will q2 instantaneously come to rest before moving back towards q1? Both charges have a mass of 25.0 milligrams. 1. A point charge q1-+5.5 microcoulombs is fixed in place. Another point charge After vi : 37% 42 rlo.cem (5 points) A point charge q1 = +7.2 microcoulombs is fixed in place. Another point charge with value q2 +2.5 microcoulombs is 15.0 cm distant from q1 and is given an initial velocity v directly towards q2. When q2 is 6.0 cm from q1 it has a velocity of 215 m/s towards q1. What was the initial velocity y of q1? Both charges have a mass of 25.0 milligrams 2. Atter -215

Explanation / Answer

1) Apply conservation of energy

U1 + K1 = U2 + K2

k*q1*q2/r1 + (1/2)*m*v1^2 = k*q1*q2/r2 + 0

9*10^9*5.5*10^-6*(-3.9)*10^-6/0.1 + (1/2)*25*10^-6*375^2 = 9*10^9*5.5*10^-6*(-3.9)*10^-6/r2

==> r2 = 1.12 m or 112 cm

2)

Apply conservation of energy

U1 + K1 = U2 + K2

k*q1*q2/r1 + (1/2)*m*v1^2 = k*q1*q2/r2 + (1/2)*m*v2^2

9*10^9*7.2*10^-6*2.5*10^-6/0.15 + (1/2)*25*10^-6*v1^2 = 9*10^9*7.2*10^-6*2.5*10^-6/0.06 + (1/2)*25*10^-6*215^2

==> v1 = 419 m/s

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