Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

. What current will flow through an iron conductor (resistivity 9.7x102m) of 12

ID: 1581579 • Letter: #

Question

. What current will flow through an iron conductor (resistivity 9.7x102m) of 12 m of length, and 2.5 mm of radius when connected to an EMF of 11 V A) 0.054A B) 18.5A C) 7.4x10 A D 1.35x10 A E) None of previous 2. The current through a resistor is measured as a function 0.3 of the voltage, what is its resistance? A) 5262 B)0.02 C) 346 D10029 E) None of previous 021 / 3. What is the power dissipated by the resistor of the previous problem when it is connected to a 10.4 V emf A) 0.019W B) 2.08 W C) 23.7 W D) 52 W E) NoP 4. The four wires are all made of the same material, The length and radius are noted, which current is the smallest? A) B) 2 Cl D42 av(v) 0.1 52 104 15.6 8 E) need more information 5. What is the power dissipated by a device that uses an EMF of 3.0 V and moves 2.1 pC in 12 ms? A) 6.3x106 W B 15.5x10 W C) 5.25x10"W D) 0.31x10"w E} None of previous e.mer/r-per 6. Rank in order from smallest to largest the currents wgI and lo- (Pcooper 1.7x10 0m and Pron-9.7x1082m) Mediun This cepper Djhello E) None of previous Irea

Explanation / Answer

1)

Current i= V/R

given that V = 11 V

Resistance is R = rho*l/A

rho = 9.7*10^-8 ohm-m

l = 12 m

A = pi*r^2 = 3.142*(2.5*10^-3)^2= 1.96*10^-5 m^2

then R = 9.7*10^-8*12/(1.96*10^-5) = 0.0594 ohm

I = V/R = 11/0.0594 = 185 A


so the correct choice is E)