Standard Exardiss Parallel Plate Capacitor and Dielectric In the circuit shown i
ID: 1581567 • Letter: S
Question
Standard Exardiss Parallel Plate Capacitor and Dielectric In the circuit shown in the figure below, the batteries have negligible internal resistance. 7.00V Interactive Exemple Current Div 500 V 1.00 3.00 Standard Exerdise Tipler6 21.P.032. 2.00 Sandard Exeraise Tipler6 23.P.065 1) Find the current in each branch of the circuit. andard Exerase Tipler6 25.P.086 A Submit You currently have 0 submissions for this question. Only 3 submission are allowed. You can make 3 more submissions for this question. Slandard Exurdiso Tipler6 23.P.028 2) 122 Tipler6 24.P.042. A Submit You currently have 0 submissions for this question. Only 3 submission are allowed. You can make 3 more submissions for this question. 3) 3 A Submit You currently have 0 submissions for this question. Only 3 submission are allowed. You can make 3 more submissions for this question. 4) Find the potential difference between point a and point b. Submit You currently have 0 submissions for this question. Only 3 submission are allowed. You can make 3 more submissions for this question. 5) Find the power supplied by each battery 5v W SubmitExplanation / Answer
let
R1=1 ohm, R2=2 ohm, R3=3 ohm
and
current through R1 is I1
current through R2 is I2
current through R3 is I3
and
V1=7v and v2=5v
1)
by using Kirchhoff's laws
V1-I2*R2 -I3*R3+V2=0
7-I2*2-I3*3+5=0 ----(1)
and
v2-I1*R1-I3*R3=0
5-I1*1-I3*3=0 ---(2)
and
I1+I2=I3 ------ (3)
by sloving above equations(1), (2) and (3)
===>
I1= 1A
I2=3 A
I3=2 A
==>
1) I1=1A
2) I2=3 A
3) I3=2 A
4)
Vab=5+I3*R3
=5+2*3
=11 v
5)
power, P=V*I
at v1=7 v
P1=v1*I2
P1=7*3
P1=21 W
and
at V2=5 v
P2=V2*I3
P2=5*2
P2=10 W
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