Step by step guide on how each problem is solved will be very much appreciated.

Question

Step by step guide on how each problem is solved will be very much appreciated. Thank you!

3) A box of mass m = 2 kg moving over a frictional floor ( b-3) has a force whose magnitude is F-25 newtons applied to it at a 30° angle, as shown in Figure 6.1 (note that equals the angle in the sketch). The crate is observed to move 16 meters in the horizontal before falling off the table (that is, d = 161 meters). An f.b.d. for the forces acting on the block is shown in Figure 6.2. f.b.d. on block Fl- 25 nts IF I sin lFlcos ld-16i mg FIGURE 6.1 FIGURE 6.2 a.) How much work does F do before the crate takes the plunge? b.)How much work does the frictional force do on the body as it moves toward the abyss? 4) Block 1 of mass "3M" is sliding along a frictionless horizontal table to the right with speed vo. Block 1 collides with block 2 of mass M that is moving to the left with speed v0. After the collision, the two blocks stick together and the blocks enter a rough surface at x=0 with a coefficient of kinetic friction that increases with distance as (x)=bx- for 0sxsd, where b is a positive constant. The blocks come to rest at x=d. The downward gravitational acceleration has magnitude "g". Determine an expression for the initial speed vo of the blocks +X frictionless

Explanation / Answer

3)

a) Work done by the Force is W = F*d*cos(theta) = 25*16*cos(30) = 346.4 J

b) Work done by Friction is Wf = -fk*d

N is the normal Force

N+ F*sin(theta) = m*g

N = mg - F*sin(theta)

N = (2*9.8)-(25*sin(30)) = 7.1 N

then

fk = mu_k*N = 0.3*7.1 = 2.13 N

then

Wf = -2.13*16 = -34.08 J

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.