A parallel plate capacitor with plate separation d is connected to a battery. Th

Question

A parallel plate capacitor with plate separation d is connected to a battery. The capacitor is fully charged to Q Coulombs and a voltage of V. (C is the capacitance and U is the stored energy.) Answer the following questions regarding the capacitor charged by à battery. For each statement below, select True or False After being disconnected from the battery, decreasing d increases U With the capacitor connected to the battery, increasing d decreases Q After being disconnected from the battery, inserting a dielectric with k will decrease C. With the capacitor connected to the battery, inserting a dielectric with k will increase U After being disconnected from the battery, inserting a dielectric with k will decrease V After being disconnected from the battery, decreasing d decreases C Submit Answer Tries 0/10 This discussion is closed Send Feedback

Explanation / Answer

False

energy stored is given as , U = (0.5) Q2/C, the charge remain same , as "d" is decreased, the capacitance "C" increase, and hence the energy U decrease.

True

charge stored is given as , Q = CV , as "d" is increased, , the capacitance "C" decrease, hence the charge stored decrease.

False ,

the capacitance increase as the dielectric is inserted.

True

as the dielectric is inserted , the capacitance "C" increase. hence the energy increase

True

as the dielectric is inserted , the capacitance "C" increase. charge stored is given as , Q = CV.since the charge remain same , the voltage V decrease

false

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