to phet.colorado.edu and search for Cicit Construction Kit: DC-Virtual Lab. Use
ID: 1581490 • Letter: T
Question
to phet.colorado.edu and search for Cicit Construction Kit: DC-Virtual Lab. Use the software to create the circuit in the figure below. The battery is 9V. The left light bulb has a resistance of 10. The top light bulb has a resistance of 8. The right light bulb has a resistance of 6(. Use the Voltmeter and Ammeter in the software to answer the following questions What is the voltage and current through the battery? Number Number What is the voltage and current through the 10 light bulb? Number Number What is the voltage and current through the 8 light bulb? Number Number What is the voltage and current through the 6 light bulb? Number NumberExplanation / Answer
given
V = 9 V ,
let R1 = 10 ohm , R2 = 8 ohm , R3 = 6 ohm
all are in series so the current will be same across each resistor
the net resistance of the the circuit is R = R1+R2+R3 = 10+8+6 = 24 ohm
thecurrent in the circuit is I = V/R = 9/24 A = 0.375 A
Battery
V = 9 V , I = 0.375 A
R1
V1 = I*R1 = 0.375*10 = 3.75 V
R2
V2 = I*R2 = 0.375*8 = 3 V
R3
V3 = I*R3 = 0.375*6 = 2.25 V
so total voltage is V = v1+v2+v3 = 3.75+3+2.25 = 9V
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