A cart is moving down an inclined plane at a constant speed 1.30 m/s. The cart c

Question

A cart is moving down an inclined plane at a constant speed 1.30 m/s. The cart collides witha stationary object and rebounds with a speed of 0.970 m/s. The mass of the cart is 0.500 kg. Find the impulse from the collision. What was the change in momentum? What was the change in kinetic energy? 4. A 10.0N force acts for 2.1 seconds on a 0.500 kg cart that is initially at rest. What is the cart's final speed, final momentum, and final kinetic energy? Assume that the cart's motion is horizontal and neglect friction. 5.

Explanation / Answer

4) initial velocity , u = -1.3 m/s

final velocity , v = 0.970 m/s

m = 0.50 Kg

impulse acting = change in momentum

impulse acting = 0.50 * (0.970 - (-1.3))

impulse acting = 1.135 Kg.m^2/s

for the change in momentum

change in momentum = 1.135 Kg.m^2/s

for the change in kinetic energy

change in kinetic energy = 0.50 * m * (v^2 - u^2)

change in kinetic energy = 0.50 * 0.50 * (0.97^2 - 1.3^2)

change in kinetic energy = -0.188 J

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