Daniel takes his two dogs. Pauli the Pointer and Newton the Newfoundland, out to
ID: 1580904 • Letter: D
Question
Daniel takes his two dogs. Pauli the Pointer and Newton the Newfoundland, out to a field and lets them loose to exercise. Both dogs sprint away in different directions, while Daniel stands still. From Daniel's point of view, Newton runs due North at 3.65 m/s, but from Pauli's point of view, Newton appears to be moving at 1.50 m/s due East. What must Paulis velocity relative to Daniel be for this to be true? Express your answer in terms of the x and y components if North is the ty direction and East is the +x-direct and then express your answer as a magnitude and an angle measured counter-clockwise from due East on, Number Number x component: m/s y component:m/s Number Number Magnitude & Direction: IIO | m/ s | @ || | | counter-clockwise from due East. o Previous Check Answer NextExplanation / Answer
a) V(P,D) = V(N,D) - V(N,P)
= -1.5 i + 3.65 j
x Component = -1.5 m/s
y Component: = 3.65 m/s
b) Magnitude = sqrt (1.52 + 3.652) = 3.95 m/s
angle = tan-1 [3.65 / 1.5] = 67.66 deg
theta = 180 - 67.66
theta = 1120 from due east
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