oo Verizon LTE8:44 PM 33% D Access WebAssign In a particular location, the horiz
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Question
oo Verizon LTE8:44 PM 33% D Access WebAssign In a particular location, the horizontal component of the earth's magnetic field has a magnitude of 1.80 10-5 T. An electron is shot vertically straight up from the ground with a speed o 1.70 106 m/s. What is the magnitude of the acceleration caused by the magnetic force? Ignore the gravitational force acting on the electron. Additional Materials (a) A proton, traveling with a velocity of 3.8 106 m/s due east, experiences a magnetic force that has a maximum magnitude of 8.7-10-14 N and a direction of due south. What are the magnitude and direction of the magnetic field causing the force? (b) Repeat part (a) assuming the proton is replaced by an electron. Additional Materials Acharge of-8.2 pC is traveling at a speed of 8.3 x 106 m/s in a region of space where there is a magnetic field. The angle between the velocity of the charge and the field is 56. A force of magnitude 5.5 10 N acts on the charge. What is the magnitude of the magnetic field? 212Explanation / Answer
F = q * v * B
a = F/m
a = q * v * B / m
a = [1.60 x 10-19 C x 1.70 x 106 m/s x 1.8 x 10-5 T] /(9.1 x 10-31) = 5.38 x 1012 m/s2
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