Question 18 of 37 A 80.3-kg linabacker ) is running at 6.71 m/s directly toward

Question

Question 18 of 37 A 80.3-kg linabacker ) is running at 6.71 m/s directly toward the sideline of a football field. He tackles 95.6-kg direction of the inebacker. As a result of the collision both players momentarily leave the ground and go out- of-bounds at an angle relative to the sideline, as shown in the diagrams below. back (On moving at 9.71 m/s straight the goal line, perpendicular to the original BEFORE IMPACT AFTER IMPACT What is the common speed of the players, immediately after their impact? Number m/ What is the angle, p, of their motion, relative to the sideline? Number

Explanation / Answer

Find the momentum using the following formula.

P = mv

Let us take downfield on the y-axis and cross-field on the x-axis.

X-momentum:

px = 80.3 kg * 6.71 m/s = 538.813 kg·m/s

Y-momentum:

py = 95.6 kg * 9.71 m/s = 928.276 kg·m/s

As the momentum is conserved, the components of the momentum after the collision is as follows

|p| = (px² + py²) = 1073.31 kg·m²

so

speed v = |p| / m

= 1073.31 kg·m² / (80.3 +95.6 ) kg

= 6.10 m/s

The direction of the momentum is the same as the direction of the velocity.

From originlal motion of linebacker.

= tan-1(928.276/538.813) = 59.86º

( or ) approximately = 59.9º

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