A load of bricks with mass m 15.6 kg hangs from one end of a rope that passes ov

Question

A load of bricks with mass m 15.6 kg hangs from one end of a rope that passes over a small, frictionless pulley. A counterweight of mass m2 28.0 kg is suspended from the other end of the rope, as shown in (Figure 1). The system is released from rest. What is the magnitude of the upward acceleration of the load of bricks? You may want to review (Pages 135-141) For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Iwo bodies with the same magnitude of acceleration. Submit Request Answer

Explanation / Answer

Newton's second law: F=ma (summed).
--> (28-15.6)*9.81 = (28+15.6)*accel
-->accel = 2.79m/s^2

Tension_Left = Tension_Right = 28*(9.81-2.79) = 196.56 N
Notice that the items are moving, so it's not the same as static tension.

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.