2/4 points | Previous Answers SerCP10 6.P.027.WI. My Notes Ask Your Teacher A 67

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2/4 points | Previous Answers SerCP10 6.P.027.WI. My Notes Ask Your Teacher A 67.0-kg person throws a 0.0485-kg snowball forward with a ground speed of 33.5 m/s. A second person, with a mass of 59.5 kg, catches the snowball. Both people are on skates. The first person is initially moving forward with a speed of 3.25 m/s, and the second person is initially at rest. What are the velocities of the two people after the snowball is exchanged? Disregard the friction between the skates and the ice. (Take the direction the snowball is thrown to be the positive direction. Indicate the direction with the sign of your answer.) thrower catcher 0.027 m/s (Give your answer to at least three decimal places.) m/s Submit Answer Save Progress

Explanation / Answer

Mass person M = 67 kg

Mass of ball m = 0.0485 kg

Speed of the ball u = 33.5 m / s

Initial speed of person U = 3.25 m / s

From law of conservation of momentum ,

Total momentum before throw = Total momentum after throw

                ( m+ M ) U = mu + Mv

From this v = [( m+ M) U - mu ] / M

                     = 3.228 m / s

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