Exercise 22.23 4 of 4 Constants Part A 0.380 m from a large insulating sheet of
ID: 1580234 • Letter: E
Question
Exercise 22.23 4 of 4 Constants Part A 0.380 m from a large insulating sheet of charge that has uniform surface charge density 4.80*10-12 C/m How much work is done on the electron by the electric field of the sheet as the electron moves from ts initial position to a point 3.00-10*2 m from the sheer? Incorrect; Try Again; 21 attempts remaining: no points deducted One or more of the units you entered is not recognized. Cick help to view a list of recognized units X o 7.3.0 Part B What is the speed of the electron when it is 3.00 10"2 m from the sheer?Explanation / Answer
field due to sheet, E = sigma / 2 e0
= (4.80 x 10^-12)/ (2 x 8.854 x 10^-12)
= 0.271 N/C
F = q E = 4.342 x 10^-20 N toward the sheet,
Work done = F.delta(x)
= (4.342 x 10^-20) (0.380 - 0.03)
= 1.52 x 10^-20 J
(B) Work done = change in KE
1.52 x 10^-20 = (9.109 x 10^-31) v^2 / 2
v = 1.83 x 10^5 m/s
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