Name: Date: Introductory Physics II Lab-Spring 2018 3. Resistors in Parallel (Fi

Question

Name: Date: Introductory Physics II Lab-Spring 2018 3. Resistors in Parallel (Figure 3) Set V = 10 v and measure Vab, wad, Va. I, 11, la, 13. 1.3 1 = 173 133 2 1, Fig. 3 b= 11 + 12 + 13 = Determine the formula relationship between I and Ii, 12, Is: In a simple circuit containing a battery followed by three resistors in parallel (as displayed in Figure 3) the voltage drop across each of the parallel resistors is equal to With the resistances you measured in Part 1, and Vab, Ved and Ver you measured above in Part 3. Use Ohm's Law to calculate I, I2, and Is. Show your formulas used and calculations below: 12 13 = How do these values compare to the measured values on the top of this page?

Explanation / Answer

For complete mathematical solution, the values of resistances R1,R2 and R3 are required.

I = V/Req = V(1/Req)

1/Req = 1/R1 + 1/R2 + 1/R3

I = V(1/R1 + 1/R2 + 1/R3)

Its a fact that the drop across the parallel combination of the resistors is always same.

Vab = Vcd = Vef = V(battery for this case)

Relationship of I

I = I1 + I2 + I3

Voltage drop across each of the parallel resistor is equal to one another and battery voltage for the given setup

I1 = V/R1 ; I2 = V/R2 ; I3 = V/R3

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