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mod/ibis/vi dIE MSN.com-Hotmail. Streaming Movies ning 18 06:00 PM 37.8/100 star Question 24 of 26 Pnnt Calculator Table / Mep a Sapling Learning A 3.31-kg object is thrown vertically upward from the surface of Venus, where the acceleration due to gravity is gi = 8.87 m/s2. The initial velocity is v. and the object reaches a maximum height of y, what is the maximum height, y2, if the object is thrown with a speed of va 1.63v from the surface of Jupiter's moon Callisto? The acceleration due to gravity on Callisto is 1.24 mS2 Give your answer as a multiple of y

Explanation / Answer

mass , m = 3.31 kg
g1 = 8.87 m/s^2
initial velocity = v1 and corresponding height reached = y1
v^2 - u^2 = 2aS
0 - v1^2 = 2 g1 y1 ...................eq 1

now when , initial launching speed = v2 = 1.63 v1 , then the corresponding height reached

v^2 - u^2 = 2aS
0 - v2^2 = 2 g2 y2
0 - (1.63v1 )^2 = 2 g2 y2 ...........eq 2
divide eq 2 by eq 1 :
1.63^2 = g2*y2 / g1*y1
y2 = 19 y1

hence required no is 19

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