Please show me the equation, all the steps, and the final answers . Thank you. 9
ID: 1579441 • Letter: P
Question
Please show me the equation, all the steps, and the final answers . Thank you.
9-3 An air puck of mass 255 g is tied to a string and allowed to revolve in a circle I table. The other end of the string passes through a hole in the center of the table, and a mass of 949 g is tied to it. The suspended mass remains in equilibrium while the puck on the tabletop revolves. Remember that drawing a free-body diagram can help you correctly apply Newton's Second Law. (a) What is the tension in the string? N(±0.02 N) b) What is the force causing the centripetal acceleration of the puck? N(±0.02 N) c) What is the speed of the puck? m/s ( ± 0.02 m/s)Explanation / Answer
Given,
mp = 255 g ; r = 1.04 m ; m = 949 g
a)In equillibrium, condidering the forces in y direction
T - Mg = 0
T = mg = 0.949 x 9.81 = 9.31 N
Hence, T = 9.31 N
b)The tension in the string causes centripital acceleration of the puck.
T = 9.31 N
c)We know that
Fc = mv^2/R
v^2 = Fc R/m = T R/m
v = sqrt (Tr/m) = sqrt (9.31 x 1.04/0.255) = 6.16 m/s
Hence, v = 6.16 m/s
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