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edugen.wileyplus.com PHYS 4A Homework 4 Cheap Car Rental- Sear https In A Nuclea

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Question

edugen.wileyplus.com PHYS 4A Homework 4 Cheap Car Rental- Sear https In A Nuclear WileyPLUS Physics question | C Halliday, Fundamentals of Physics, 10e PRINTER VERSTON BACK ASSIGNMENT RESOURCES Chapter 05, Problem 023 (Ch.5) Crapter 05, Concept Question 0 Chapter 05, concept Tarzan, who weighs 857 N, swings from a cliff at the end of a 15.6 m vine that hangs from a high tree limb and initially makes an angle of 17.1° with the vertical. Assume that an x axis points horizontally away from the cliff edge and a y axis extends upward. Immediately after Tarzan steps off the cliff, the tension in the vine is 819 N. Just then, what are (a) the force from the vine on Tarzan in unit-vector notation, and (b) the net force acting on Tarzan in unit-vector notation? What are (c) the magnitude and (d) the direction (measured counterclockwise from the positive x-axis) of the net force acting on Tarzan? What are (e) the magnitude and (f) the direction of Tarzan's acceleration just then? 005 (a) Number (b) Number (c) Number (d) Number j Units 008 j Units Units 032 Units Cha Units a cha(e) Number 051 (f) Number Units Click if you would like to Show Work for this question: Open Show Work Review Score Review Results by Study LINK TO SAMPLE PROBLEM Question Attempts: Unlimited SAVE FOR LATER SUBMIT ANSWER

Explanation / Answer

Here, we will assume that the vine hangs from a point beyond the cliff, otherwise Tarzan wouldn't go anywhere.

Given that -

theta 17.1 deg

so -  
fx = 819 * sin(17.1) = 240.8 N
fy = 819 * cos(17.1) = 782.8 N

(a) Force from the vine on Taron, f = (240.8i + 782.8j) N

(b) W = 857 N; m = w/g = 857 / 9.81 = 87.4 kg
Now, define fn=net force
fnx = fx = 240.8 N
fny = fy-w = 782.9 - 857 = -74.1 N

So, fn = (240.8i - 74.1j) N

(c) |(fn)| = sqrt(fnx^2+fny^2) = sqrt[240.8^2 + (-74.1)^2] = 252 N

(d) angle(fn) = arctan(fy/fx) = arctan(-74.1 / 240.8) = -17.1 deg = 180+17.1

= 197.1 deg (counterclockwise from positive x-axis)

(e) mag(a) = Magnitude (fn) / m = 252 / 87.4 = 2.88 m/s^2

(f) angle(a) = angle(fn) = 197.1 deg.